Hello , Why does an incoming photon can only scatter from an electron if the electron is not bound top an atom ? What happens when an electron in an atom absorbs a photon? Otherwise it will not. Let us suppose you are in a dark room. The electron stays in the first excited state, having absorbed the photon. I think it would be clearer to talk about the structure or corporeity of the photon on one side and on the other side about its energy content. on the 'electric' charge. the hypotrons with charge +1/3 and -1/3. They aren't inconsistent with fractional charges. The criticism to the CERN and the selling of their research using fantastic names is fully shared with you. How does this sound? But we have also 8 different types of gluons for the bonding task. If the spring vibrates it has an oscillatory energy. "On the question of the electromagnetic momentum of a charged body". and why proton/antiproton and electron/positron are the only stable particles with charge 1. and why there are just 4 types of 'force' mediating particles with zero-charge. Metaphysical expressions don't count-unless they can be identified with  calculations, in which case, personal opinions don't matter (the word ``adversity'' is meaningless in this discussion). In that context the absorption of a photon means that the energy packet goes into somemthing else, but the carrier (the "informaton) put his way further with the speed of light. This includes observers that are equipped with the most sophisticated measuring instruments. 3. Let us thus express it this way: the corporeity of the bulb is preserved when it is not shining. There is no restriction on occupying the higher energy levels,so it can occupy 2s,2p etc,it will depend upon the photon energy absorbed by the electron.we can use hw/2pi=Ef-Ei Ef=energy of final level Ei=energy of initial level. The QOD (Quantum Orbital Dynamics) approach only resorts on a structural wave function and to quantum numbers such as those for atomic structural orbitals, i.e. Inversely, when some energy is transferred to a virtual particle it becomes then an easily observable particle. symmetric gravitational fields can be derived in a WKB-like expansion in 1/c Orbital model of the structure of elementary particles, https://www.researchgate.net/publication/301585930_Space_this_great_unknown, https://www.researchgate.net/publication/305774508_ELECTROMAGNETISM_EXPLAINED_BY_THE_THEORY_OF_INFORMATONS-2, ELECTROMAGNETISM EXPLAINED BY THE THEORY OF INFORMATONS-2, https://en.wikiversity.org/wiki/Hilbert_Book_Model_Project/Information_Messengers#The_absorption_dilemma, https://www.researchgate.net/publication/299234932_SECRETS_BEHIND_THE_MACH-ZEHNDER_PHENOMENON_1A, https://www.researchgate.net/project/Hypotron-Theory, http://kreuzer-dsr.de/kdsr/bulletin/KDSR_HypotronTheory_Flyer.pdf, SECRETS BEHIND THE MACH-ZEHNDER PHENOMENON, https://www.rand.org/content/dam/rand/pubs/research_memoranda/2006/RM2820.pdf, http://www.lkb.upmc.fr/cqed/wp-content/uploads/sites/14/2016/06/Recife.2008.2.pdf, https://www.researchgate.net/publication/313900108_Deuteron_project, https://www.researchgate.net/publication/1998821. The nuance is very important. The Standard Model uses 6 types of quarks, but since these are “coloured” (they are tri-chromatic) this ends up giving 18 “coloured” quarks. An alternative would be a relativistic semi-classical approach, since the kinetics of the q electric charge carrier of the orbital structure is expected to be relativistic, i.e. The idea that a photon is a structured compact object surrounded by some fluctuating massless dipoles allows to understand the Mach-Zehnder phenomenon qualitatively in a "classical" manner without any mystical arguments concerning "interference" of "probability waves". The photon is not conceived as been formed by a pair e+ e- but by a pair q+ q-. During travel, warps keep their shape and their amplitude. or if there is a net dipole moment, excites some lattice vibration. and what can be considered as the reason why a nucleus decays at all. What happens to the photon when it is absorbed? It is a negative energy (bonding energies are negative) since it is the energy that has to be transferred to dissociate it. The difference stands in that the two charges q+ and q- acquire their quantum state as e+ and e- only after they get free once the photon is dissociated. 3. What happens when an electron in an atom absorbs a photon? The focus is on experiments, that go beyond ``thought experiments'' since the theory is known. What happens? I said: a photon can be interpreted as a bound state of q+ and q-. C what color is the emitted photon d what happens to. For instance, the electric dipole approximation is always forbidden and in principle the photon could remain "alive" for ever. But in its absorption by a material it just loose the energy related to its wavelength without loosing its structural bonding energy of 1.02 MeV, energy that should be brought by the absorber in order to get dissociated. with a single electron, represented in the picture at: points out the complexity that may have the structural orbital of elementary particles. the atom ejects a photon. Frankly, if you have only electric charge I cannot understand how you can get a so different interaction of the ordinary electromagnetic interaction just changing the state of the charges? Now let us apply this consideration to the mass associated with elementary particles and consider it proceeding from the quantum state of their structural orbital, which allows us to easily understand the reason for the vast multitude of masses, as it corresponds to a wide variety of structural quantum states, and hence the analogy with the atom. This process can be described by the action of an operator on the state of n photons that, indeed, destroys a photon and that's why it's called an annihilation operator. If one hasn't, then focusing on the sociology is, simply, meaningless-and this ought to have been noticed as being part of any scientific field. first time submission experiences). I point out that the energy that may be carried by any particle should be well differentiated from the bonding energy that its structure may have (an energy that is conventionally considered negative) since it represents the input energy that should be provided to the particle to dissociate it. How long do you wait to hear from a journal after you have submitted your manuscript? Unless this issue is addressed, the model is useless. They just carry a Lorentz index and only gauge invariant quantities are relevant. Thus the conservation of pairs depend strongly of the energy that you are considering. What happens when an object absorbs light? I understand that the abelian U(1) unitary group can be associated to the electric charge the same as, U(1) ----->   1 electric charge (complex number rotation S1), SU(2) -----> 3 flavour charge (quaternions S2 Pauli matrices), SU(3) -----> 8 color charge (biquaternions S3 Dirac matrices). ", Professor John Blamire, electrons and energy, BIOdotEDU. What would happen if someone spilled water on the moon? How to abandon the intuitive notion of the 'continuum' by some appropriate mathematical theories seems to be an open question. Why its magnetic moment has a value of -4.70589 nm and not another one? the electric dipoles of ONE type of an 'ultimate building block of matter and radiation', that is in the mentioned Hypotron Theory. American Journal of Physics, 28(7), 1960, p. 639-643, Prykarpatsky A.K., Bogolubov N.N. Maths is a specific language created by the mankind in an effort to describe (always incompletely) physical processes. I didn’t get at first what you wanted to exactly stress. Observers perceive in spacetime format, while at the situation of the observed event the information is available in the Euclidean format. The atom absorbs or emits light in discrete packets called photons, and each photon has a definite energy. That energy is not a binding enegy, it just has that energy. In terms of dipole, it is the energy necessary to break apart the dipole. (The description of natural phenomena is mathematical, nothing more and nothing less. While the sociology of the two endeavors has diverged, one ought to know better-if one's studied physics. The opposite happens when an electron emits a photon. Besides, wrong predictions are discarded, so we are left only with those that presumably coincide with experimental detections. Both answers above are more correct of course but I thought it might help you to understand thinking of it the way I had to ;) When you eat (absorb) you can jump to a higher energy level and when you give all your food away (emit) you will fall to a lower energy level. And all its properties can be deducted from that, taking into account how the week interaction Hamiltoniam acts on these states. has been achieved, nothing to do with the argument you are trying to make. If the sample is not very thick, it can come out with diminished amplitude. Available from: For those who are not familiar with the complexity that may have structural orbitals I am posting a picture of a variety of structural atomic orbitals, as an example of the complexity that can be expected for the structural orbitals of elementary particles, accessible at:. The photon breaks thus the rule as being an energy carrier without a coupled mass. Because the known particles have properties beyond that of electric charge, that's why. He (the photon) wants to know if it is going to “die out” in being absorbed or if he will just loose its energy (his energetic put on) but save the “body”. If it transfers its oscillatory energy to an external material it looses its energy, but the spring is still alive, it has not disappeared. Please be respectful of what is said and do not come up with distorted interpretations. Where do photons go in absorption? the electromagnetic field. I'll give you an easy example, a hydrogen atom, has one electron. The particles inherit these properties. This doesn't mean that one is computing the mass of the muon, however and there's a reason for that, that's well understood. And this means that for the transition to be possible at all, additional degrees of freedom must be specified, in order that all the usual conservation laws (i.e. I suggest another one, more basic : "The smallest transferable part of an electromagnetic radiation". One does this sort of activity for one's own satisfaction. The argument is that if a theory must be fine-tuned, then there should be an underlying physical reason for such values. In addition, this property of photon (very weak electric dipole) can describe the absorption and emission energy by charged particles. I have already valued your elsewhere clever comments on the CMB. Is a fine-tuned theory that is fundamentally wrong, but can still produce correct predictions useful? Do you believe the modern approach to cosmology is fundamentally flawed? Sole physical entity that exists no mass its energy should be more interesting if you right... Possess a footprint, which formulation to use is a decay of the relaxes! 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